Section 20: Problem 1 Solution »

Section 20: The Metric Topology

is a metric on if is a non-negative symmetric function such that  iff , and the triangle inequality holds. is called the distance between and .
is a metric space if is a metric on and the topology on (called the metric topology induced by ) is generated by the basis consisting of -balls centered at , , for all and . A topological space is called metrizable if there is a metric on that induces .

General properties

  • The topology induced by is the coarsest topology on such that is continuous.
  • The standard bounded metric corresponding to is . and induce the same topology.
    • Another example of a bounded metric inducing the same topology as is .

Standard metrics on

  • is the euclidean metric on if where .
  • is the square metric on if .
  • is the uniform metric on if .
    • The uniform metric induces the uniform topology.
    • For , where . is open in the box topology but not in the uniform topology.
  • is a metric that induces the product topology on .

Properties

  • The euclidean and square metrics induce the standard topology on .
    • And so does every metric of the form for .
  • The box topology on is finer than the uniform topology which is finer than the product topology. If is infinite, all three are different.
  • , for all , which is a homeomorphism relative to the box and product topologies, is continuous relative to the uniform topology iff ’s are bounded from above, and is a homeomorphism iff ’s are bounded from below and above by some positive numbers.

Metrization of

(in the box or product topology) is metrizable only if is countable and the topology is the product topology.
  • The metric is one that induces the product (box and uniform) topology on .
  • The metric is one that induces the product topology on .
  • As we shall see in §21, if and is metrizable, then there is a sequence of elements of converging to .
    • in the box topology is not metrizable. If then in the box topology, but there is clearly no sequence of elements of converging to in the box topology. A similar argument works for all infinite .
    • in the product topology is not metrizable if is uncountable. If , then in the product topology, but, if is uncountable, then for any sequence of points of there is some such that for all , hence, does not converge to in the product topology.

Subspaces of

is the subset of consisting of all sequences such that converges. Then, the topology induced by on is called the -topology.
is the subset of consisting of all sequences that are eventually zero.
  • equals in the box topology, the set of all sequences of real numbers converging to in the uniform topology, and in the product topology.
  • The -topology is strictly finer than the uniform topology on , but strictly coarser than the box topology (both inherited from ).
  • When all four (box, , uniform, and product) topologies are inherited by , they are all distinct.
  • When all four (box, , uniform, and product) topologies are inherited by the Hilbert cube, , the box topology is strictly finer than the other three topologies which become equal.